If we know a girl's score in the entrance exam, a bit of maths lets us work out what percentage of candidates did better or worse than her; and if we also know how many candidates took the exam, we can work out approximately how many girls did as well or better.
According to the "Frequently Asked Questions" document on the Kendrick School website (http://www.kendrick.reading.sch.uk/admissions/admission-year-7-september-2016/), in 2015 a total of 1250 girls took the exam (598 at the school plus another 652 at other venues).
The same document says that 321 candidates achieved the qualifying score, of whom 173 are in the designated area, i.e. approximately 53.9% are in the designated area. The calculator below makes an assumption that this proportion is constant across the distribution of scores.
Remember, there are 96 places available for Kendrick School September 2016 intake, and of course some people who are in the top 96 and are offered places will not take them up, so a ranking outside the first 96 may still be good enough to gain a place at the school.
According to the "Frequently Asked Questions" document on the Kendrick School website (http://www.kendrick.reading.sch.uk/admissions/admission-year-7-september-2016/), in 2015 a total of 1250 girls took the exam (598 at the school plus another 652 at other venues).
The same document says that 321 candidates achieved the qualifying score, of whom 173 are in the designated area, i.e. approximately 53.9% are in the designated area. The calculator below makes an assumption that this proportion is constant across the distribution of scores.
Remember, there are 96 places available for Kendrick School September 2016 intake, and of course some people who are in the top 96 and are offered places will not take them up, so a ranking outside the first 96 may still be good enough to gain a place at the school.
Enter number of candidates who sat the exam below, then click "Calculate":
[For anybody who wants to know more about the calculation, I believe that the scores are worked out by assuming a normal distribution, calibrating the scores so that the mean is 100 and the standard deviation is 15. So you can fiddle with the maths yourself by using Microsoft Excel and entering a formula of =NORMDIST(score, 100, 15, TRUE) in a cell, replacing score with your daughter's score. This gives the proportion of candidates below that score e.g. if she scores 113, you need to type =NORMDIST(113, 100, 15, TRUE) . To convert it to a percentage, multiply by 100, like this =100 * NORMDIST(113, 100, 15, TRUE) . The tool above does all this for you.]